getcalc.com's Fraction Simplification Calculator is an online basic math function tool to reduce the fraction number to its lowest terms. This calculator, formula, workout and associated information may help students, teachers or professionals to learn, teach or execute such calculations manually.
The fractions can't be reduced further if it meets any one of the following criteria.
1. prime number in either numerator or denominator.
2. GCD (Greatest Common Factor) as 1 for numerator and denominator.
- (x+5) 2 would be typed (x+5)^2. You can put a fraction in an exponent. X 2/3 should be typed like x^(2/3). With more complicated fractions you have to use parenthesis. For example if you typed x^2+1/x-5, you might think this means 'the quantity 'x-squared plus 1' over the quantity 'x minus 5'.' Actually, this site would correctly put 1/x as the.
- Windows Management Framework (WMF) 5.0 brings functionality that has been updated from WMF 4.0. WMF 5.0 is available for installation only on Windows Server 2012 R2, Windows Server 2012, Windows 2008 R2, Windows 8.1, and Windows 7 SP1.
(x+5) 2 would be typed (x+5)^2. You can put a fraction in an exponent. X 2/3 should be typed like x^(2/3). With more complicated fractions you have to use parenthesis. For example if you typed x^2+1/x-5, you might think this means 'the quantity 'x-squared plus 1' over the quantity 'x minus 5'.' Actually, this site would correctly put 1/x as the. These packages are no longer supported by the development team. 1.0.5 Windows Windows Installer: MAC OS X: Linux 32 Bit Linux 64 Bit: Source code hosted on Gcode: 1.0.4 Windows: MAC OS X: Linux 32 Bit Linux 64 Bit: Source code hosted on Gcode: 1.0.3 Windows: MAC OS X: Linux 32 Bit Linux 64 Bit: Source code hosted on Gcode. You need to make a 1:5 dilution of a solution. You need 10 ml of the diluted solution. How much initial sample and diluent should you use? Answer: 1:5 dilution = 1/5 dilution = 1 part sample and 4 parts diluent in a total of 5 parts. If you need 10 ml, final volume, then you need 1/5 of 10 ml = 2 ml sample.
Answers for Laboratory Calculation Problem Set #1
1. You need to make a 1:5 dilution of a solution. You need 10 ml of thediluted solution. How much initial sample and diluent should you use?
Answer: 1:5 dilution = 1/5 dilution = 1 part sample and 4 partsdiluent in a total of 5 parts. If you need 10 ml, final volume, then you need1/5 of 10 ml = 2 ml sample. To bring this 2 ml sample up to a total volume of10 ml, you must add 10 ml - 2 ml = 8 ml diluent.
2. How would you prepare 500 ml of a 10% NaCl solution?
Answer: In this problem, the % solution is the number of gramssolute in 100 ml solvent, so a 10% solution of NaCl is 10 grams NaCl in 100 mlwater. But you need 500 ml, final volume, so 10 g x 5 = 50 g NaCl.
3. If you have DNA with a concentration of 2 µg/µl, how much DNA(in µl) must be added to make a 20 µl solution with a DNAconcentration of 1 µg/µl?
1. You need to make a 1:5 dilution of a solution. You need 10 ml of thediluted solution. How much initial sample and diluent should you use?
Answer: 1:5 dilution = 1/5 dilution = 1 part sample and 4 partsdiluent in a total of 5 parts. If you need 10 ml, final volume, then you need1/5 of 10 ml = 2 ml sample. To bring this 2 ml sample up to a total volume of10 ml, you must add 10 ml - 2 ml = 8 ml diluent.
2. How would you prepare 500 ml of a 10% NaCl solution?
Answer: In this problem, the % solution is the number of gramssolute in 100 ml solvent, so a 10% solution of NaCl is 10 grams NaCl in 100 mlwater. But you need 500 ml, final volume, so 10 g x 5 = 50 g NaCl.
3. If you have DNA with a concentration of 2 µg/µl, how much DNA(in µl) must be added to make a 20 µl solution with a DNAconcentration of 1 µg/µl?
Answer: Since you know the initial concentration (2 µg/µl),the final concentration (1 µg/µl), and the final volume (20 µl),the following formula can be used to calculate the amount of DNA needed(initial volume)
- (initial concentration)(initial volume) = (finalconcentration)(final volume)
- (2 µg/µl)(X µl) = (1 µg/µl)(20 µl)
- X µl = (1 µg/µl)(20 µl) / 2 µg/µl
- X µl = 10 µl DNA
4. You have a 10x TBE buffer. To run a gel, you need 500 ml of a 2xsolution of TBE. How do you make a 500 ml solution of 2x TBE buffer from the10x buffer?
Answer: Since you know the initial concentration (10x), the finalconcentration (2x), and the final volume (500 ml), you can use the formula:
- (initial concentration)(initial volume) = (finalconcentration)(final volume)
- (10x)(X ml) = (2x)(500 ml)
- X ml = (2x)(500 ml) / 10x
- X ml = 100 ml of 10x TBE
Then, to calculate the amount of water needed, use the following formula:
- final volume - initial volume = volume of diluent
- 500 ml total - 100 ml of 10x TBE = 400 ml water
5. You want to make a 0.5% agarose gel. How much agarose (in grams) do youneed to make up a 50 ml gel solution?
Answer: There are at least two methods for solving this question(as with many dilution problems): logically and mathmatically.
- Logically:
- 0.5% means 0.5 grams in 100 ml, so if you only need 50 ml, you need 0.5 g /2 = 0.25 g agarose for a 50 ml gel solution.
- Mathematically:
- 0.5 g/100 ml = X g/50 ml
- (0.5 g) (50 ml)/100 ml = X g
- 0.25 g = X g
6. What is the DNA concentration of a 50 µl solution which contains 10µl of DNA at a concentration of 4 µg/µl?
Answer: There are two ways to solve this problem:
- Calculate the total amount of DNA in the solution, then divide by thetotal volume:
- 10 µl x 4 µg/µl = 40 µg of DNA
- 40 µg DNA/ 50 µl = 0.8 µg/µl
- Just plug the values into the formula:
- (initial concentration)(initial volume) = (final concentration)(finalvolume)
- (4 µg/µl)(10 µl) = (X µg/µl)(50 µl)
- X µg/µl = (4 µg/µl)(10 µl) / 50 µl
- X µg/µl = 0.8 µg/µl
7. How would you make a 3x TBE buffer from a 12x TBE buffer for a totalvolume of 200 ml?
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Ik multimedia amplitube 4 complete v4 0 3 download free. Answer: Since you know the initial concentration (12x), the finalconcentration (3x), and the final volume (200 ml), you can use the formula:
- (initial concentration)(initial volume) = (final concentration)(finalvolume)
- (12x)(X ml) = (3x)(200 ml)
- X ml = (3x)(200 ml) / 12x
- X ml = 50 ml of 12x TBE
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Then, to calculate the amount of water needed;
- 200 ml final volume - 50 ml initial volume of 12x TBE = 150 ml water(diluent)
Thanks are given to Tim Allen and the MMG graduate students for providingthese problems.
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